1 比特与 2 比特字符

// Java solution using Java Streams
// The problem is similar, but we will use streams to simplify the traversal
// Since Java Streams do not support easy index-based traversal, we use IntStream and a manual counter
 
import java.util.stream.IntStream;
 
public class Solution {
    public boolean isOneBitCharacter(int[] bits) {
        int n = bits.length;
        int[] i = {0};
        IntStream.range(0, n - 1).forEach(idx -> {
            if (i[0] >= n - 1) return; // Exit if already beyond second last character
            if (bits[i[0]] == 1) {
                i[0] += 2;
            } else {
                i[0] += 1;
            }
        });
        return i[0] == n - 1;
    }
}