差值数组不同的字符串

// Java Stream Solution
// This solution uses Java Streams to calculate the difference arrays and then finds the unique one.
// It leverages the stream API for filtering and processing collections.

import java.util.*;
import java.util.stream.*;

public class SolutionStream {
    public String oddStringOut(String[] words) {
        int n = words[0].length();

        // Calculate the difference array for each word using streams
        List<int[]> differences = Arrays.stream(words)
            .map(word -> IntStream.range(0, n - 1)
                .map(i -> word.charAt(i + 1) - word.charAt(i))
                .toArray())
            .collect(Collectors.toList());

        // Find the unique difference array
        for (int i = 0; i < differences.size(); i++) {
            int[] diff = differences.get(i);
            long count = differences.stream().filter(d -> Arrays.equals(d, diff)).count();
            if (count == 1) return words[i];
        }
        return null; // Just to satisfy the return type, should not reach here
    }
}