从链表中删去总和值为零的连续节点

/*
  In this approach, we use a combination of Java Stream to iterate and filter elements.
  However, since LinkedList manipulation can't fully be achieved with Stream alone, 
  we will still use basic loops to manage nodes. The Stream will primarily help in handling
  collections and sequences.
*/

import java.util.HashMap;
import java.util.stream.Stream;

class ListNode {
    int val;
    ListNode next;
    ListNode(int x) { val = x; }
}

public class Solution {
    public ListNode removeZeroSumSublists(ListNode head) {
        ListNode dummy = new ListNode(0);
        dummy.next = head;
        HashMap<Integer, ListNode> prefixMap = new HashMap<>();
        int prefixSum = 0;
        prefixMap.put(0, dummy);

        Stream.iterate(dummy, node -> node.next != null, node -> node.next).forEach(node -> {
            prefixSum += node.val;
            if (prefixMap.containsKey(prefixSum)) {
                ListNode start = prefixMap.get(prefixSum).next;
                int sum = prefixSum + start.val;
                while (sum != prefixSum) {
                    prefixMap.remove(sum);
                    start = start.next;
                    sum += start.val;
                }
                prefixMap.get(prefixSum).next = start.next;
            } else {
                prefixMap.put(prefixSum, node);
            }
        });
        return dummy.next;
    }
}