转化时间需要的最少操作数

/*
 * This implementation is similar to the basic Java solution but utilizes Java Streams where applicable.
 * We still calculate the difference in minutes and use a greedy approach to minimize operations.
 * The difference is calculated using streams and we use a stream for operations calculation as well.
 */
import java.util.stream.Stream;

public class TimeConverterStream {
    public int convertTime(String current, String correct) {
        int currMinutes = Stream.of(current.split(":"))
                                 .mapToInt(Integer::parseInt)
                                 .reduce(0, (a, b) -> a * 60 + b);
        int corrMinutes = Stream.of(correct.split(":"))
                                 .mapToInt(Integer::parseInt)
                                 .reduce(0, (a, b) -> a * 60 + b);
        int diff = corrMinutes - currMinutes;
        return Stream.of(60, 15, 5, 1)
                     .mapToInt(inc -> {
                         int result = diff / inc;
                         diff %= inc;
                         return result;
                     }).sum();
    }
}