矩形面积

/*
 * Problem Statement:
 * Given two rectangles on a 2D plane where the edges are parallel or perpendicular to the axes,
 * calculate and return the total area covered by both rectangles.
 * Each rectangle is defined by its bottom-left vertex (ax1, ay1) and top-right vertex (ax2, ay2)
 * and (bx1, by1) and (bx2, by2) for the second rectangle.
 */
 
import java.util.stream.IntStream;
 
public class RectangleAreaStream {
    public static int computeArea(int ax1, int ay1, int ax2, int ay2, int bx1, int by1, int bx2, int by2) {
        // Calculate the area of the first rectangle
        int area1 = (ax2 - ax1) * (ay2 - ay1);
        // Calculate the area of the second rectangle
        int area2 = (bx2 - bx1) * (by2 - by1);
 
        // Calculate the overlapping area using streams
        int overlapWidth = IntStream.of(ax2, bx2).min().getAsInt() - IntStream.of(ax1, bx1).max().getAsInt();
        int overlapHeight = IntStream.of(ay2, by2).min().getAsInt() - IntStream.of(ay1, by1).max().getAsInt();
        int overlapArea = (overlapWidth > 0 && overlapHeight > 0) ? overlapWidth * overlapHeight : 0;
 
        // Total area is the sum of individual areas minus the overlapping area
        return area1 + area2 - overlapArea;
    }
 
    public static void main(String[] args) {
        // Example 1
        System.out.println(computeArea(-3, 0, 3, 4, 0, -1, 9, 2)); // Output: 45
        // Example 2
        System.out.println(computeArea(-2, -2, 2, 2, -2, -2, 2, 2)); // Output: 16
    }
}